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$defined(x[0] = val) causes an error instead of returning false when a type does not have []= defined #2454
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@@ -7,6 +7,7 @@
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### Fixes
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- Compiler assert with var x @noinit = 0 #2452
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- Confusing error message when type has [] overloaded but not []= #2453
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- $defined(x[0] = val) causes an error instead of returning false when a type does not have []= defined #2454
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### Stdlib changes
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