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Remove lambda code that should never happen.

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This commit is contained in:
Christoffer Lerno
2025-08-04 22:13:37 +02:00
parent 90990ed2f3
commit 5292e08cd6
1 changed files with 4 additions and 9 deletions
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13
src/compiler/sema_expr.c
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@@ -10083,11 +10083,7 @@ static inline bool sema_expr_analyse_lambda(SemaContext *context, Type *target_t
{
Decl *decl = expr->lambda_expr;
if (!decl_ok(decl)) return false;
if (decl->resolve_status == RESOLVE_DONE)
{
expr->type = type_get_func_ptr(decl->type);
return true;
}
assert(decl->resolve_status != RESOLVE_DONE);
Type *flat = target_type ? type_flatten(target_type) : NULL;
if (flat)
{
@@ -10224,19 +10220,18 @@ static inline bool sema_expr_analyse_lambda(SemaContext *context, Type *target_t
}
expr->type = type_get_func_ptr(decl->type);
// If it's a distinct type we have to make a cast.
expr->resolve_status = RESOLVE_DONE;
expr_rewrite_const_ref(expr, decl);
// If it's a distinct type we have to make a cast.
if (target_type && expr->type != target_type && !cast_explicit(context, expr, target_type)) return false;
if (multiple)
{
vec_add(original->func_decl.generated_lambda, decl);
}
decl->resolve_status = RESOLVE_DONE;
expr_rewrite_const_ref(expr, decl);
return true;
FAIL_NO_INFER:
SEMA_ERROR(expr, "Inferred lambda expressions cannot be used unless the type can be determined.");
return false;
RETURN_SEMA_ERROR(expr, "Inferred lambda expressions cannot be used unless the type can be determined.");
}
static inline bool sema_expr_analyse_ct_feature(SemaContext *context, Expr *expr)